Getting the day of the year

Author :

use this function (usage example given in code) to get the day of the year on a specified date. date is specified by giving the day, month and year.

PHP Example :

<? /* Aug 15th, 2003 sploit */ /* specify date. d = day, m = month, y = year */ $d = 2; $m = 2; $y = 2000; /* display date and day of the year (on that date) */ if(day_of_year($m, $d, $y)) { echo "date: ", date("d-M-Y", mktime(0,0,0, $m, $d, $y)); echo "<BR>day of the year: ", day_of_year($m, $d, $y); } else { echo 'invalid date!'; } /* FUNCTION: day_of_year($month_number, $day_number, $four_digit_year) if date specified is correct, returns the day of the year else returns false */ function day_of_year($m, $d, $y) { if(checkdate($m, $d, $y)!=true) { return false; } for($i=1 ; $i < $m; $i++) { $timestamp = mktime (0,0,0,$i,1,$y); $num_days_in_month = date("t", $timestamp); $day_of_year = $day_of_year + $num_days_in_month; } $day_of_year = $day_of_year + $d; return($day_of_year); } ?>